AQA A-level Physics 7408 · Paper 1 · Spec 3.2.1

Particles and Antiparticles

Build nuclei, make matter from light, draw weak interactions and test reactions against the conservation laws. Free simulations, exam questions and a printable booklet.

On this page: ● particle · ● antiparticle (bar over the symbol, or the opposite charge sign such as e+) · ∿ photon or W boson (wavy line) · in interaction diagrams, arrows point forward in time and an antiparticle’s arrow points backwards

What is inside an atom?

Choose a nucleus on the stability chart and watch the atom change: Its nuclide notation, charge and specific charge. Switch between the Bohr and quantum models of the electrons. Unstable nuclei can be made to decay. The second tab shows the strong nuclear force that holds the nucleus together.

The atom (not to scale)
Background photons
Make it decay
Electrons6
Charge
Mass
Specific charge
The stability chart: Decay selector
Protons, Z6
Neutrons, N8
Chart view

Click the chart to choose a nucleus, or use the ▼ and ▲ buttons (hold to go faster).

Black dots are the stable nuclei: Together they make the line of stability, which bends away from the N = Z line for heavier nuclei. Above it nuclei have too many neutrons (β− decay); below it too many protons (β+ decay or electron capture); very heavy nuclei decay by alpha emission.

A nucleus, stable or unstable, can exist only in the shaded band. Outside it, the protons and neutrons cannot hold together: A nucleon would leave at once, so no nucleus can form there.

Stable nuclei and the decays of well-known radioactive nuclei are real data. Other nuclei follow the region they are in, a model prediction. Positron capture (n + e+ → p + νe) is allowed by the conservation laws but needs a place full of positrons, such as the early Universe. Radioactive decay and this chart come again in Nuclear physics (3.8.1).

Mass uses 1.67 × 10−27 kg per nucleon plus 9.11 × 10−31 kg per electron. e = 1.60 × 10−19 C.

Particle A
Particle B
Forces between two protons (model · motion slowed down enormously)

Drag particle B towards particle A, then let go. Keyboard: Arrow keys on the picture.

Separation
Strong nuclear force
Electrostatic force
Resultant force on B
Potential energy

Positive force = repulsive (pushes B away), negative = attractive. Electrostatic force from F = Q1Q24πε0r2 (exact). The strong force has no simple equation: Its values here are a model, right to an order of magnitude. The real motion lasts about 10−22 s; here it is slowed down enormously, and sped up further where the forces are tiny (shown on the picture).

This is a classical model. In reality only a proton and a neutron stay together as a pair: The deuteron, the nucleus of hydrogen-2. When they join, the extra energy leaves as a gamma photon (so the motion here is damped to let B settle). Two protons or two neutrons on their own do not stay together.

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The Particle Family

Every particle in this topic has a place on this chart. Click any box to see what it is, its values from the AQA data booklet and how it comes up in the exam. Switch to the wider Standard Model to see what lies beyond A-level.

QuarksLeptonsExchange particlesHadronsClick any box for details

The pion is a meson (made of quarks), but in the A-level model it is also the exchange particle of the strong force between nucleons, so it appears in both places. Rest energies are from the AQA Data and Formulae Booklet where it lists them.

Hadron Builder and Conservation Laws

Drag quarks into the circle and press Check to see whether they make a hadron. Then test reactions: A reaction can happen only if charge, baryon number and both lepton numbers balance. Strangeness tells you which interaction it uses.

Rules for a hadron

  • Baryon: Three quarks (B = +1). Antibaryon: Three antiquarks (B = −1).
  • Meson: One quark and one antiquark (B = 0).
  • Each quark has B = +⅓ and each antiquark B = −⅓, so B must come out as a whole number. The charge Q must be a whole number too.
  • Strangeness: s has S = −1, s has S = +1.
Particle
—
Class
—
Charge Q
—
Baryon number B
—
Strangeness S
—
Is this reaction possible?

For each quantity, is it conserved? Then press Check.

Is each quantity conserved?
QuantityConserved?BeforeAfter

Quark composition (AQA data booklet)

Quark composition of hadrons
ParticleQuarksQBS

Quarks

Properties of quarks
QuarkQBS
u+⅔+⅓0
d−⅓+⅓0
s−⅓+⅓−1
AntiquarksOpposite signs

Lepton numbers

Lepton numbers
ParticlesElectron lepton numberMuon lepton number
e−, νe+10
e+, νe−10
μ−, νμ0+1
μ+, νμ0−1

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Particle properties from the AQA Data and Formulae Booklet. Energy and momentum are always conserved too: A single particle at rest can decay only into particles with less total rest energy.

Antimatter: Annihilation and Pair Production

A particle and its antiparticle have the same mass and rest energy, but opposite charge. When they meet they annihilate into two photons. A photon with enough energy can do the reverse and make a particle–antiparticle pair.

Annihilation
normal
Rest energy E0
Kinetic energy Ek (each)
Speed of each particle
Energy of each photon
Frequency f = Eh
Wavelength λ = hcE
Pair production
Pair to make
normal
Photon energy Eγ
Minimum 2E0 for this pair
Kinetic energy of each particle
Speed of each particle
Photon wavelength
PET scanner (positron emission tomography · a brain scan with a fluorine-18 tracer)
Inside the tracer: One fluorine-18 nucleus undergoes β+ decay
normal

How a PET scanner works

  1. Inside the tracer. The patient is injected with a sugar (glucose) labelled with fluorine-18. Fluorine-18 is proton-rich, so it undergoes β+ decay: a proton becomes a neutron and the nucleus becomes oxygen-18, giving out a positron and an electron neutrino. Its half-life is about 110 minutes, long enough to make and inject the tracer, short enough to keep the dose low.
  2. Annihilation. The positron travels only about 1 mm through tissue before it meets an electron. They annihilate into two gamma photons, each 0.511 MeV (the rest energy of an electron), travelling in opposite directions so that momentum is conserved.
  3. Only some photons are detected (see the side view and the view from above). The patient lies on a bed with a ring of detectors round the head. Only photon pairs travelling in the plane of the ring hit two detectors; the rest are missed and leave the scanner.
  4. The line of response (see the end view). Two detectors on opposite sides of the ring register photons at the same moment. The annihilation happened somewhere on the straight line between them (the line of response).
  5. The detector chain. In each detector a crystal (scintillator) turns the gamma photon into a flash of light; a photomultiplier tube turns the flash into an electrical pulse; a coincidence circuit accepts the pair only if both pulses arrive within a few nanoseconds; the computer records the line.
  6. The computer builds the image. Millions of lines are recorded. Where many lines cross, there is a lot of tracer. Busy brain tissue uses most glucose, so the grey matter of the cortex shows red and yellow, while the fluid-filled ventricles and the skull show blue and purple. The image becomes clearer the longer the scan runs: Press Run the scanner and watch it build up.
Side view
View from above
End view: Head and shoulders inside the ring
The computer builds the image

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Photons are drawn as wave packets: A short burst of wave inside an envelope. Gamma rays cannot be seen, so the purple is only a code; a more energetic photon has a shorter wavelength (drawn wavelengths are not to scale). Particle speeds use special relativity, E0 + Ek = E0 / √(1 − v2/c2) (not needed for this topic); on screen, photons move at c and particles at their real fraction of c. Rest energies from the AQA Data and Formulae Booklet. h = 6.63 × 10−34 J s, c = 3.00 × 108 m s−1, 1 MeV = 1.60 × 10−13 J.

Drawing Interaction Diagrams

Particles interact by swapping exchange particles. Press Play to watch each interaction happen: A “now” line moves up the time axis, the particles move along their lines and the exchange particle travels as a wave packet from one vertex to the other, drawing its wavy line behind it. Check that charge balances at every vertex.

On the AQA specification

Beyond A-level

β− decay
normal

Equation
Exchange particle
Interaction

House style: Time runs up the page; each particle is a straight line with its symbol at the end and an arrow in the direction of time (an antiparticle’s arrow points backwards); the line bends where the particle changes; the exchange particle is a wavy line between two vertices, sloping upwards because it moves forwards in time; a W has an arrow showing which way it travels (from the vertex that emits it to the vertex that absorbs it). W bosons are drawn in blue, photons in purple. At quark level the quark that changes is drawn in red.

Key equations for particles and antiparticles

Photon energy
AQA formula sheet
E = hf = hcλ
E in J, f in Hz, λ in m; h = 6.63 × 10−34 J s
Rest energies and properties
AQA data booklet
e, μ, π, K, p, n
Rest energies in MeV; quark and lepton tables with Q, B, S, L
Specific charge
Useful relationship: learn it
chargemass
In C kg−1. Use the charge of the whole ion or nucleus
Neutron number
Useful relationship
N = A − Z
A nucleon number (top), Z proton number (bottom)
Energy units
Useful relationship: learn it
1 MeV = 1.60 × 10−13 J
1 eV = 1.60 × 10−19 J
Annihilation (at rest)
Useful relationship
Ephoton = E0
Two photons, each with the rest energy of one particle
Pair production
Useful relationship
Emin = 2E0
Any extra photon energy becomes kinetic energy
Change of quark character
Useful relationship
β−: d → u   β+: u → d
Only the weak interaction changes a quark’s type

Quick catch

Three rounds of five multiple-choice questions, each round harder than the last. Pick A, B, C or D and the reasons appear straight away. Get 4 of 5 right to unlock the next round.

0 of 5 right

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Where it comes from

Three ideas behind this topic, built up step by step. The neutrino hypothesis is on the AQA specification; the two-photon argument uses momentum, which you meet again in the mechanics topics; the third tab is for interest.

1
Momentum before
An electron and a positron, both at rest, meet. Their total momentum is zero.
pbefore = 0
2
One photon is impossible
A single photon always carries momentum, so it could not have zero momentum. Momentum would not be conserved.
3
Two photons, opposite directions
Two photons of equal energy travelling in opposite directions have equal and opposite momenta, which add to zero.
p1 + p2 = 0
4
Share the energy
Energy is conserved: The two photons share the total rest energy 2E0, so each has E0.
hf = E0 = 0.511 MeV for e− and e+
Annihilation at rest
e−e+γγelectron and positron at rest; photons with equal energiestravel in opposite directions
A PET scanner uses this: The two 0.511 MeV gamma photons reach detectors on opposite sides of the patient at the same moment.
1
A fixed amount of energy
Every beta decay of a given isotope releases the same total energy, because the nucleus before and after is the same each time.
2
Only two products?
If only the daughter nucleus and the beta particle were produced, every beta particle would get the same kinetic energy.
3
The puzzle
Measured beta particles have a continuous range of kinetic energies, from almost zero up to a maximum. Energy seemed to go missing.
4
Pauli’s answer (1930)
A third particle, with almost no mass and no charge, carries away the rest of the energy, so energy is conserved. For β− decay it is the electron antineutrino.
Ek, beta + Ek, antineutrino = constant
Kinetic energies of beta particles
Emaxkinetic energy of beta particlenumber of beta particlesa continuous range,not one single energy
The maximum energy Emax is the energy released in each decay. A beta particle has it only when the antineutrino takes almost nothing.
Not examined by AQA. AQA asks only which exchange particle goes with each interaction. This tab shows why the weak interaction is so short range.
1
Borrowed energy
An exchange particle is virtual: It exists only briefly. Making it needs its rest energy, and the heavier it is, the shorter the time it can exist.
2
Time and range
Even at nearly the speed of light, a particle that exists for a very short time cannot travel far. The range of the force is about c times that time.
3
Heavy W, short range
The W boson has a rest energy of about 80 000 MeV, about 85 times that of a proton, so the weak interaction reaches only about 10−18 m.
4
Massless photon, infinite range
The photon has no rest mass, so the electromagnetic force has an infinite range, falling off with distance.
heavier exchange particle → shorter range
Exchange particles and ranges
Exchange particles
InteractionExchange particleRest energyRange
electromagneticvirtual photon0infinite
strong (between nucleons)pionabout 140 MeVabout 1–3 × 10−15 m
weakW+, W−about 80 000 MeVabout 10−18 m
The pion row shows the same idea: A lighter exchange particle, a longer range, which matches the reach of the strong nuclear force.

Test yourself

35 exam-style questions in three levels: Core, Exam-style and Stretch for A*. Each level shows a few at a time. Press Try another question for a different one. Type numbers without units. For the explain parts, write your answer, then mark it against the mark scheme.

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Download the booklet

Notes, worked examples, equation cards, 21 quick checks and 30 exam-style questions on particles and antiparticles, to print and write on. The answers are at the back.

Particles and Antiparticles: Notes and practice booklet

Print it, write in the spaces, then check your answers at the back.

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Particles and antiparticles: Common questions

Why does beta-minus decay give an antineutrino, not a neutrino?

Lepton number must be conserved. Before the decay there are no leptons, so the electron-lepton number is 0. The electron that is made has Le = +1.

n → p + e− + νe    Le: 0 → 0 + 1 − 1 = 0

To bring the total back to zero, the third particle must have Le = −1: An electron antineutrino. In β+ decay the positron has Le = −1, so a neutrino is emitted instead.

Exam trap. Writing νe in a β− equation loses the mark, even if everything else is right.

Why do annihilation photons go in opposite directions?

When a particle and its antiparticle annihilate at rest, their total momentum is zero. The photons must carry zero total momentum too.

A single photon always has momentum, so at least two photons are needed. Two photons with equal energies travelling in exactly opposite directions have momenta that cancel. Each photon gets the rest energy of one particle: 0.511 MeV for an electron and a positron.

Exam trap. Each photon has E0, not 2E0. The total energy is 2E0, shared between two photons.

Why are strange particles made in pairs?

Strange particles are made by the strong interaction, which conserves strangeness. In a collision between ordinary hadrons, such as protons and pions, the total strangeness is 0.

π− + p → K+ + K− + n    S: 0 → +1 − 1 = 0

So for every particle with S = −1 made, there must be one with S = +1. The strange particles then decay by the weak interaction, which lets strangeness change by 1. That is also why they live so long.

Exam trap. A change in strangeness does not make a reaction impossible: It means it can only be a weak interaction. A change of 2 or more is impossible.

Is the W a meson?

No. The W+ and W− are W bosons, the exchange particles of the weak interaction. They are not made of quarks.

Mesons, such as pions and kaons, are hadrons made of a quark and an antiquark. The pion is the exchange particle of the strong nuclear force between nucleons, which may be where the mix-up comes from.

Exam trap. “W meson” is marked wrong. Write W boson, and give its charge: W− in β− decay, W+ in β+ decay and electron capture.